Two stones are thrown vertically upward from the ground, one with three times the initial speed of the other. assume free fall.
part a :
if the faster stone takes 8.00 s to return to the ground, how long will it take the slower
stone to return? t= ?
part b :
if the slower stone reaches a maximum height of h, how high (in terms of h) will the faster stone go?
Vf = 0
g = 9.8 m/s^2
Vo = g* t => t up = Vo / g
t total = 2*t = 2*Vo / g
t slow = 2*Vo / g
t fast = 2*[3Vo] / g = 6Vo / g => Vo = g * t fast / 6 = 9.8 m/s^2 * 8.00 s / 6 = 13.07 m/s = Vo
t slow = 2 * 13.07 m/s / 9.8 m/s^2 = 2.67 s.
Vf ^2 = Vo ^2 - 2gy
Vf = 0 => Vo ^2 = 2gy
Vo ^2 = 2gH
[3Vo]^2 = 2gy
=> [3Vo]^2 / Vo^2 = 2gy / 2gH
=> 9 = y/H => y = 9H
The answer would be D, when the plastic strip and cloth are rubbed together there is a transfer of electrons from the plastic strip to the cloth leaving the plastic strip positively charged as it lost electrons, while the cloth becomes negatively charged.
yea some data is shown what is the question dude