Physics, 12.11.2019 04:31, nnance4784

An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only a rope and a bag of tools. first he tries to throw a rope to his fellow astronaut, but the rope is too short. in a last ditch effort, the astronaut throws his bag of tools in the direction of his motion, away from the space station. the astronaut has a mass of ma=113 kgma=113 kg and the bag of tools has a mass of mb=13.0 kg. mb=13.0 kg. if the astronaut is moving away from the space station at =1.20 m/svi=1.20 m/s initially, what is the minimum final speed ,fvb, f of the bag of tools with respect to the space station that will keep the astronaut from drifting away forever?

Answers: 2

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Answered: baidentheodore617

15.75 m/s

Explanation:

v = Velocity of the combined mass of astronaut and tools = 1.8 m/s

m_1 = Mass of astronaut = 124 kg

m_2 = Mass of tools = 16 kg

v_1 = Velocity of astronaut = 0

v_2 = Velocity of tools

As linear momentum is conserved

$m_1v_1 + m_2v_2 =(m_1 + m_2)v\\\Rightarrow v_2=\frac{(m_1 + m_2)v-m_1v_1}{m_2}\\\Rightarrow v_2=\frac{(124+16)\times 1.8-124\times 0}{16}\\\Rightarrow v_2=15.75\ m/s$

The velocity of the tools is 15.75 m/s

Answered: negativechill

15.8m/s

Explanation:

This problem can be solved by taking into account the conservation of the momentum. In this case the momentum of the astronaut and the bag of tools must equal the momentum of the astronaut and the bag of tool after the astronaut throws the bag.

Hence, we have

$p_{before}=p_{after}\\(m_{a}+m_{b})v=m_{a}v_{a}+m_{b}v_{b}$

where ma and va are the mass and velocity of the astronaut, mb and vb are the mass and velocity of the bag, after the astronaut throw the bag. The velocity v is the velocity where the astronaut has the bag of tool

By taking into account that the velocity of the astronaut must be zero to keep him near of the space station, we have that vb = 0.

Thus

$(124 + 19.0)2.10=19.0v_{b}\\v_{b}=\frac{300.3}{19.0}=15.8m/s$

Answered: scottbrandon653

The minimum final speed of the bag of tools (with respect to the space station) that will keep the astronaut from drifting away forever is 15.81 m/s.

Explanation:

To solve the question, we list out the variables as follows,

Mass of astronaut, m₁ = 124 kg

Mass of the bag of tools, m₂ = 19.0 kg

Initial velocity of astronaut, v₁ = 2.10 m/s = Initial velocity of bag of tools v₂

Final velocity of astronaut, v₃ = 0 m/s, assuming the astronaut is brought to a stop

Velocity of the bag of tools = v₄

We can observe that the question is about conservation of linear momentum. Therefore we have, from the principle of conservation of linear momentum.

Initial total momentum = Final Total momentum

We then have

m₁v₁ + m₂v₂ = m₁v₃ - m₂v₄

Since v₁ = v₂ we have

(m₁ + m₂) × v₁ = m₁v₃ - m₂v₄

Plugging the values and solving for the required unknown variable we have

(124 kg + 19.0 kg) × 2.10 m/s = 124 kg × v₃ - 19.0 kg × v₄

Since v₃ = 0 m/s, we have

300.3 kg·m/s = 0 kg·m/s - 19.0 kg × v₄

∴ v₄ = $\frac{300.3 kg\cdot m/s}{19,0 kg}$ = 15.81 m/s

The minimum final speed of the bag of tools (with respect to the space station) that will keep the astronaut from drifting away forever = 15.81 m/s.

Answered: samueltaye

The velocity of the bag will be 16.08 m/s

Explanation:

Given:

Mass of the astronaut, M = 124 kg

Mass of the bag, m = 10 lg

Initial speed of the astronaut with bag, v_i = 1.20 m/s

Applying the concept of conservation of momentum

we have

(M + m) v_i = Mv₁ + mv₂

here,

v₁ is the final velocity of the astronaut = 0

v₂ is final velocity of the bag

thus, on substituting the values, we have

(124 + 10)1.20 = 124 × 0 + 10v₂

v₂ = 16.08 m/s

Hence, the velocity of the bag will be 16.08 m/s

Answered: Visitor

Iwould sure like to answer your question but i honestly just don’t know

Answered: Visitor

a.) travels faster in solids because the particles are closer together.

air is a gas water is a liquid

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An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the...