Aperson pushing a horizontal, uniformly loaded, 23.90 kg23.90 kg wheelbarrow of length is attempting to get it over a step of height ℎ=0.=0.370r, where is the wheel's radius. the center of gravity of the wheelbarrow is in the center of the wheelbarrow. what is the horizontal component pxpx of the minimum force p⃗ p→ necessary to push the wheelbarrow over the step? the gravitational acceleration is =9.81 m/s2.
The horizontal component of the minimum force is 144.24 N.
Loaded = 23.90 kg
Height = 0.370 R
Where, R=wheel's radius
We need to calculate the acceleration
Using formula of acceleration
Put the value into the formula
We need to calculate the horizontal component of the minimum force
Using moment about center of point of contact
Hence, The horizontal component of the minimum force is 144.24 N.
hypothesising or postulating
i believe the answer would be:
d. violin, clarinet, french horn, and tuba