Consider two particles a and b. the angular position of particle a, with constant angular acceleration, depends on time according to =θ₀+ω₀t+12αt² . at time t=t₁, particle b, which also undergoes constant angular acceleration, has twice the angular acceleration, half the angular velocity, and the same angular position that particle a had at time t=0.how long after the time t₁ does the angular velocity of b have to be to equal a's?
After time "t" the angular position of A is given as
now we know that B start motion after time t1
so its angular position is also same as that of position of A after same time "t"
so we have
now since both positions are same
you have to draw the persons position over there
1 is a answer of a question