Apoint charge, q = −0.3 µc and m = 3 × 10−16 kg, is moving through the field e = 30az v/m. use eq. (1) and newton’s laws to develop the appropriate differential equations and solve them, subject to the initial conditions at t = 0, v = 3 × 105ax m/s at the origin. at t = 3 µs, find (a) the position p(x, y, z) of the charge; (b) the velocity v; (c) the kinetic energy of the charge.
The Newton second law using to determinate position
So at t=3us
To x at t=3us
Velocity now, derive the position can get the velocity of the function so
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