g(x) = 3 cos 2x + 1
when x = 0 g(x) = 3 cos 0 + 1 = 3*1 + 1 = 4
so the answer is g(x)
g(x) has greatest y-intercept.
We are given a table of values for function f(x) as:
We know that the y-intercept of a function is a point where the x-value is zero.
i.e. the input value is zero.
Hence, after looking at the table of values of the function f(x) we have the y-intercept of the function f(x) is:
Also we are given function g(x) as:
g(x) = 3 cos(2x) + 1
Hence, we calculate the y-intercept of the function g(x) by taking x=0
on taking x=0 we have:
Hence, the y-intercept of function g(x) is 4.
Hence, g(x) has the greatest y-intercept.