Use the given conditions to write an equation for the line in​ point-slope form and​ slope-intercept form. slope = -8, passing through (-5,-4)

M=-8

(-5, -4)
x1, y1

y-y1=m(x-x1)
=
y-5=-8(x-5)

OR

y=m(x-x1)+y1
=
y= -8(x-5)+-4

3-(-5) 8 4
——— = —- = —-
3-(-3). 6 3

I will do the work only for Slope-Intercept form, as to preserve time. (I will still provide the answer, just not the work for point slope)

Slope = 

Substitute
y2 = 13
y1 = -3
x2 = 3
x1 = -3
Slope = 

Simplify
Slope = 

Solve
Slope = 
Slope = 16/6

Simplify
Slope = 8/3
y = 8/3x + B

Now we find B (substitute 3,13 for x and y)
13 = (8/3)(3) + B

Solve for B
B = 5
y = 8/3x + 5 is the slope-intercept answer
and
8x − 3y + 15 = 0 is the point slope answer

Let
A (-5,-4) and B (5,10)

Part 1) write an equation for the line in​ point-slope form

we know that
the equation of a line in​ point-slope form is
y-y1=m*(x-x1)

step 1
find the slope m
m=(y2-y1)/(x2-x1)> m=(10+4)/(5+5)> m=14/10---> 7/5

strep 2
with m=7/5 and the point B (5,10)
find the equation of a line
y-y1=m*(x-x1)> y-10=(7/5)*(x-5)

the answer Part 1) is
y-10=(7/5)*(x-5)

Part 2) write an equation for the line in​ slope-intercept form

we know that
the equation of a line  in​ slope-intercept form is
y=mx+b

step 1
find the slope m
m=(y2-y1)/(x2-x1)> m=(10+4)/(5+5)> m=14/10---> 7/5

step 2
with m=7/5 and the point B (5,10)
find b
y=mx+b
10=(7/5)*5+b> 10=7+b> b=3

the equation of the line is
y=(7/5)x+3

the answer Part 2) is
y=(7/5)x+3

y +5 = -5(x +6)y = -5x -35

Step-by-step explanation:

For a line with slope m through point (h, k), the point-slope form of the equation is ...

  y -k = m(x -h)

For your point and slope, the line is ...

  y +5 = -5(x +6)

__

Adding -5 and simplifying puts this in slope-intercept form.

  y = -5x -30 -5

  y = -5x -35

Y-y1=m(x-x1) Y+5=7/3(x+3) Y+5=7/3x+7 That one it's point-slope form Y+5=7/3x+7 -5 -5 Y=7/3x+2 That one it's slope-intercept form.