50 sq. units
Join one diagonal of the trapezoid ABCD.
Assume that AC is the diagonal.
So, Area of the trapezoid = Area of Δ ABC + Area of Δ CAD.
Now, coordinates of A(-2,2), B(2,5), C(11,-7) and D(1,-2) are given.
We know, that three vertices of a triangle are , and respectively, then the area of the triangle will be given by
Hence, area of Δ ABC will be
Again, area of Δ CAD will be
Therefore, the area of the trapezoid ABCD will be (37.5 + 12.5) = 50 sq, units. (Answer)
the answers c
false : it can not go to 9 the highest that part can go is 7
here is your proof