Mathematics
Mathematics, 12.11.2019 05:31, mariah9695

G= -5r+13g=βˆ’5r+13g, equals, minus, 5, r, plus, 13
g=g=g, equals
-2
hint #11 / 3
to find the output, \greend{g}gstart color #1fab54, g, end color #1fab54, we need to substitute \blued{3}3start color #11accd, 3, end color #11accd into the equation for \blued{r}rstart color #11accd, r, end color #11accd.
hint #22 / 3
\begin{aligned} \greend{g}& =-5\blued{r}+13 \greend{g}& =-5\cdot\blued{3}+13 & =-15+13 & =\greend{-2} \end{aligned}
g
g
​

=βˆ’5r+13
=βˆ’5β‹…3+13
=βˆ’15+13
=βˆ’2
​

+get another hint (2/3)
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G= -5r+13g=βˆ’5r+13g, equals, minus, 5, r, plus, 13
g=g=g, equals
-2
hint #11 / 3

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