Assume that the readings at freezing on a batch of thermometers are normally distributed with mean 0°c and standard deviation 1.00°c. find , the 60-percentile of the distribution of temperature readings. this is the temperature reading separating the bottom 60% from the top 40%.
We are given the following information in the question:
Mean, μ = 0
Standard Deviation, σ = 1.00
We are given that the distribution of readings at freezing on a batch of thermometers is a bell shaped distribution that is a normal distribution.
We have to find
P(X<x) = 0.0600
We have to find the value of x such that the probability is 0.600
P(X < x)
Calculation the value from standard normal z table, we have,
no this is a nonlinear negative