Mathematics, 12.11.2019 03:31, thedocgalloway

In may you used 700 kilowatt-hours of energy for electricity.
a. calculate the total electrical energy used in joules
b. calculate the average power use in watts
c. assume that your power supplier generates electricity by burning oil. note that 1 liter of oil releases 12 million joules of energy. how much oil is needed to generate the electricity you use? give answer in both liters and joules.

i am really having a hard time with this..

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Answered: allenpaietonp9v8sv

1 kilowatt-hours = 3.6x10^6 joules

Converting 900 kilowatt-hours to joules, we have:

900*(3.6*10^6)=3.24*10^9 joules, or

Total Electrical Energy use = 3,240,000,000 joules

"The total electrical energy use was 3,240,000,000 joules."

The month of May has 31 days and 1 day is 24 hours. So May has:

31*24=744 hours

Now, we divide 900 kW-hr by the number of hours in the month (744 hrs) to get average power use:

kW. Since 1000 Watts = 1 kW, we multiply this by 1000 to get the answer in Watts:

1.21 * 1000 = 1210 Watts

Part 1:

The conversion efficiency of most generating stations is 33%. So we need to multiply the total electrical energy use (in joules) by a factor of 3 to get the amount of joules required. So:

(3.24 * 10^9)*3 = 9.72 * 10^9 joules

We divide this by 12 million joules to get the number of liters:

So, 810 liters is needed

Part 2:

We know that 0.2642 gallons is equal to 1 liters. To get the number of gallons needed, we multiply 810 by 0.2642. So:

810 * 0.2642 = 214.00 gallons

"To generate the electricity you used, 214.00 gal is needed."

Answered: graciearany

The specific heat of metal is 0.507 J/g°C

Explanation:

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

m_1 = mass of metal = 24.87 g

m_2 = mass of water = 76.12 g

$T_{final}$ = final temperature = 28.2°C

T_1 = initial temperature of metal = 104.0°C

T_2 = initial temperature of water = 25.2°C

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

$24.87\times c_1\times (28.2-104)=-[76.12\times 4.186\times (28.2-25.2)]$

c_1=0.507J/g^oC

Hence, the specific heat of metal is 0.507 J/g°C

Answered: jorell

The answer is 1/24

Step-by-step explanation:

Hope this Helps!!:)

Would appreciate Brainliest!!:)

Answered: molly7654

The answer would be -5/12

Answered: anenee1

The main reason that Wilson's dream of a "peace without victory" failed at the end of World War I was because "d. France and England wanted to punish Germany for starting the war," since this led to harsh reparation payments that quickly crippled the Germany economy even further.

Answered: Visitor

step-by-step explanation:

Answered: Visitor

345

step-by-step explanation: