Jimmy’s dad gave him $100 on his birthday, which is january 1. jimmy deposited the $100 in his savings account the same day. at the beginning of every month thereafter, jimmy decides to deposit three times the amount he did in the previous month. on june 15 of the same year, the amount in jimmy’s account will be $
how much money will be in jimmy's account?
I think its $36,400 because jan- 100 feb- 100x3=300 march- 300x3=900 april- 900x3=2,700 may- 2,700x3=8,100 june 8,100x3=24,300 then add them all together 100+300+900+2,700+8,100+24,300= 36,400
We are given that a finite geometric series
We have to calculate sum of finite geometric series
First term = $100
Second term= 3 times the amount in previous month=$300
Third term =$900
Total months =6
Common ratio ,r=
when r> 1
Hence, the amount in Jimmy's account will be $36400.
He will deposit 3 times the amount deposited during the previous month.
Amount of money deposited by Jimmy on February 1 = $300
Amount of money deposited by Jimmy on March 1 = $900
Amount of money deposited by Jimmy on April 1 = $2700
Amount of money deposited by Jimmy on May 1 = $8100
Amount of money deposited by Jimmy on June 1 = $24300
On June 15 of the same year, the amount of money that will be in Jimmy's account = (100 + 300 + 900 + 2700 + 8100 + 24300) dollars
we know that
therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.
looking at the function
, what should the value of x be, such that the input in the function becomes 7?
we simply equate the terms,
thus, the point on the new function would be
can you give me more detail on this! ?