, 12.11.2019 10:31, kingtaco321

Which shows 23^2017^2 being evaluated using the difference of perfect squares method? a.23^3017^2=(529+289)(5290289)=196, 320 b.23^2017^2=5290289=240 c.23^2017^2=(23+17)(23017)=(40)(6)= 240 d.23^2017^2=(23017)^2=(6)^2=36

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