This might be wrong but because there are only 6 sides on a number cube, and only two numbers between this probablity this is the most likely correct answer. I apologize if this is wrong.
3 of 6 chances
When we roll a die, we can get 1,2,3,4,5,6
There are 6 possible outcomes
The even numbers are 2,4,6
There are 3 ways to get an even number
P(even number) = number of evens/ total outcomes
The probability is 1/6
A cube has 6 sides
Only one side of the cube has 2 on it
The probability of getting 2 would be 1/6
Only one side of the cube has 6 on it
The probability of getting 6 would be 1/6
For both events to happen together
1/6 x 1/6 = 1/36
The correct answer between all the choices given in question number 1 is C and in question number 2 is D. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.
y is 35/4.
your exact question is kind of difficult to understand, so maybe an example will explain what you're supposed to do? i'll work through the first problem on the worksheet.
suppose you have a tray of 652 brownies, and you have 5 friends that you want to feed without picking favorites. how many brownies can you dole out to each of your friends in equal amounts? how many will be left over for you to eat?
what you're doing here is finding a way to arrange the number 652 as the sum of integer multiple of 5 and some remainder:
here ("q" for quotient) is the number of brownies each of your friends get, and is the remainder. that's the basic idea behind division.
we break up the number 652 into parts so that the leading digit stands on its own:
652 = 600 + 52
first we check if it's possible to hand out exactly 100 brownies to each friend. with 5 friends, this means we want to know if we can take out 500 brownies from the tray. we can do this 1 time because we have 600 brownies to take from, and when we do that we're left with 100 + 52 brownies to divvy up. so we know that
652 = 1*500 + 152
next we want to know if it's possible to hand out exactly 10 brownies per friend. if we can, we have to remove 50 brownies from the tray each time until we can't. we have 152 brownies left, and we know that 3(50) = 150, so
152 = 3*50 + 2
now we have 2 brownies left in the tray. is it possible to hand 1 out to each of your 5 friends? no, you'd need a minimum of 5 brownies to do that. so the last 2 are yours.
putting everything together, we found that
652 = 1*500 + 3*50 + 2
and we can rearrange this to write
652 = 5*100 + 5*30 + 2
652 = 5(100 + 30) + 2
652 = 5*130 + 2
so and .
you might be more accustomed to the table depicting the algorithm. that's just a compact way of organizing what we've done above. you can consult the image i've attached below.
you roll a number cube. you roll a number that is greater than 2 and les...