Engineering, 01.12.2020 21:50, malak3782

# For the sake of simplicity, let’s say that the solar flux at the moon’s distance from the sun is the same as the solar flux at Earth’s distance from the sun.
a) The moon has essentially no atmosphere, and “moonlight” is solar flux reflected by the moon. What is the average intensity of “moonlight” immediately above the illuminated hemisphere of the moon? For the sake of simplicity, let’s assume that “moonlight” is reflected with even intensity from the entire illuminated hemisphere of the moon. Write an expression, then solve. (hint: We know that the area of a disk, such as the moon’s disk, is Pi*r2, and that the surface area of a sphere is 4Pi*r2. So, what’s the surface area of a hemisphere relative to a disk?)

b) Starting with the value you calculated for (a), calculate the flux of “moonlight” at the Earth-moon distance from the moon. Continue, and calculate the flux of “moonlight” after it goes through the atmosphere. (Tip: Light that passes through the atmosphere is light that is not reflected by the atmosphere.)

Answers: 2

Engineering, 04.07.2019 18:10, ahmedeldyame

Aloaded platform of total mass 500 kg is supported by a dashpot and by a set of springs of effective stiffness 72 kn/m. it is observed that when the platform is depressed through a distance x = 12.5 cm below its equilibrium position and then released without any initial velocity; it reaches its equilibrium position in the shortest possible time without overshoot. find the position and velocity of the loaded platform 0.10 sec. after its release. if a further load of 400 kg is added to the platform, find, i) the frequency of damped vibrations, and i) the amplitude of vibration after 2 complete oscillations, given that the initial amplitude is 15 cm.

Answers: 1

Engineering, 04.07.2019 18:10, johnthienann58

Thermal stresses are developed in a metal when its a) initial temperature is changed b) final temperature is changed c) density is changed d) thermal deformation is prevented e) expansion is prevented f) contraction is prevented

Answers: 2

Engineering, 04.07.2019 18:10, jojoangelique13

The flow rate of air through a through a pipe is 0.02 m5/s. a pitot static tube is placed in the flow. the radius of the pitot static tube is 1 mm. assuming the flow to be steady and the air to be at 300k, calculate the difference in total and static pressure if the diameter of the pipe is: (a) d 0.1 m d 0.05 m (c) d 0.01 m

Answers: 2

For the sake of simplicity, let’s say that the solar flux at the moon’s distance from the sun is the...

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