Part A: CH₃COCH₃
CH₃COCH₃ is a nonelectrolyte, which means it does not dissociate when it dissolves in water. Therefore, the only solute present will be the undissociated CH₃COCH₃.
Part A: In an aqueus solution there are three solute particles: H3O+, HCOO- and HCOOH
Part B: HCOOH(aq) + H2O(l) ⇄ HCOO-(aq) + H3O+(aq)
Weak acids don't completely ionize in solution, for this reason, a formic acid solution contains un-ionized acid, it means there are many intact molecules of formic acid and only a fraction of the dissolved molecules ionize to form H3O+(aq) and HCOO-(aq).
The chemical equation is:
HCOOH(aq) + H2O(l) ⇄ HCOO-(aq) + H3O+(aq)
The double arrows in this equation indicate that the ionization can occur in both the forward and reverse directions.
hope this : )
the answer would be a