As the temperature of a solvent increases, the solubility of any gas dissolved in that solvent decreases.
when the temperature of a river, lake or stream is raised high , due to discharge of hot water from some industrial process the solubility of the oxygen in the water is decreased .The fish and the other organisms that live in the water bodies such as rivers, ponds, lakes etc can survive only in the presence of oxygen and decrease in the concentration of the water due to increased temperature can lead to the death of the fish and this may in turn damage the ecosystem.
In the above example, water is considered as the solvent and the oxygen is considered as the solute. When the temperature of the solvent that is water increases, the solubility of the gas that is oxygen in the solvent decreases.
Therefore the answer is decreases.
Negative is it can't be broken down and makes the air polluted. Positive, it can be re used again and again.
a) 18.81% is the mass percent (m/m) of the KCl solution.
b) 3.643 M is the molarity of the KCl solution.
c) 0.6073 M is the molarity of the diluted KCl solution.
a) mass on of evaporating dish = 24.10 g = x
mass on of evaporating dish and KCl solution = 44.30 g = y
After heating, mass on of evaporating dish and dry KCl = 27.90 g = z
Mass of KCl solution = y - x = 44.30 g - 24.10 g = 20.2 g
Mass of KCl in solution = z - x = 27.90 g - 24.10 g = 3.8 g
The mass percent (m/m) of the KCl solution;
18.81% is the mass percent (m/m) of the KCl solution.
b) Moles of KCl =
Volume of the KCl solution = 14.0 mL = 0.014 L ( 1 mL = 0.001 L)
Molarity of the solution :
3.643 M is the molarity of the KCl solution.
Molarity of KCl solution before dilution =
Volume of the solution before dilution =
Molarity of KCl solution after dilution =
Volume of the solution after dilution =
0.6073 M is the molarity of the diluted KCl solution.
That is the answer I believe!