Asmall barber shop has a single chair and an area for waiting, where only one person can be in the chair at a time, and no one leaves without getting their hair cut. so the system is roughly: entrance → wait → haircut → exit assume customers arrive at the rate of 10 per hour and stay an average of 0.6 hour. what is the average number of customers in the barber shop? (round your answer to 1 decimal place.)
There are 6 customers in the barber shop on an average.
As per the Little's law, the average number of costumers or individuals in a system (L) can be calculated by multiplying the average arrival rate (λ) and the average time each customer spends in the system (W).
The algebraic expression, is as follows:
L = λW
L=inventory or average number of customers in the system.
λ=arrival rate = 10
W=flow time average customer spends in the system = 0.6
L = 0.6 * 10 = 6
Thus, there are 6 customers in the barber shop on an average.
i believe that it is a 45% chance.