Option B, increases
If we arrange NaC2H3O2, we will get CH3COONa. As it is dissolved in water, it dissociates into ions
Positive ion - Na+
Negative ions - CH3COO-
In chemistry, electrical conductivity is defined as the amount of ionic concentration in a solution. With dissociation of CH3COONa, the ionic concentration increases and hence the electrical conductivity also increases.
hence, option B is correct